Justin Cyder
12,624 posts
35 months

Can we get over the 200km typo & move on?


SystemParanoia
9,696 posts
84 months

isnt geosync orbit 26,000km ... not 200km


annodomini2
5,098 posts
137 months

SystemParanoia said: isnt geosync orbit 26,000km ... not 200km Geostationary is 35786Km. Geosynchronous varies depending on the required position and can be elliptical.


BarnatosGhost
7,920 posts
139 months

annodomini2 said: SystemParanoia said: isnt geosync orbit 26,000km ... not 200km Geostationary is 35786Km. Geosynchronous varies depending on the required position and can be elliptical. Does that depend on the mass of the satellite?


MartG
3,831 posts
90 months

SystemParanoia said: isnt geosync orbit 26,000km ... not 200km The ISS is not in geosynchronous orbit  it is only 200  300km up

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Eric Mc
77,281 posts
151 months

Currently the ISS's maximum altitude is just under 400km.
That is the highest we are going with manned spacecraft technology at the moment. Obviously, 40 years ago we were taking people out 250,000 miles.
Unmanned is a different story. The "highest" unmanned probes are the Voyagers and Pioneers 10 and 11.


Simpo Two
60,085 posts
151 months

Eric Mc said: That is the highest we are going with manned spacecraft technology at the moment. Obviously, 40 years ago we were taking people out 250,000 miles. Won't be long before H&S limit this to a 3m scaffold tower surrounded by rubber matting and 8 blokes in hard hats.


Eric Mc
77,281 posts
151 months

I wonder how well a rubber mat would cope with a 25,000 mph impact.


Simpo Two
60,085 posts
151 months

If you fell off the top of the 3m tower you wouldn't be doing 25,000mph (unless it was a neutron star, in which case the tower would be a flat disc along with the blokes in hard hats so the question doesn't really arise)


Eric Mc
77,281 posts
151 months

Simpo Two said: If you fell off the top of the 3m tower you wouldn't be doing 25,000mph (unless it was a neutron star, in which case the tower would be a flat disc along with the blokes in hard hats so the question doesn't really arise) And a very, very thin mat.


annodomini2
5,098 posts
137 months

BarnatosGhost said: annodomini2 said: SystemParanoia said: isnt geosync orbit 26,000km ... not 200km Geostationary is 35786Km. Geosynchronous varies depending on the required position and can be elliptical. Does that depend on the mass of the satellite? No, hence why a feather and a hammer fall at the same rate on the moon. The mass only has an impact for the launcher and orbital maintenance.


BarnatosGhost
7,920 posts
139 months

annodomini2 said: BarnatosGhost said: annodomini2 said: SystemParanoia said: isnt geosync orbit 26,000km ... not 200km Geostationary is 35786Km. Geosynchronous varies depending on the required position and can be elliptical. Does that depend on the mass of the satellite? No, hence why a feather and a hammer fall at the same rate on the moon. The mass only has an impact for the launcher and orbital maintenance. When you say orbital maintenance, do you mean they need to exert a force to stay in position (beyond small tweaks here and there)? I ask because that doesn't seem intuitive to me. Swinging a 1kg weight on a 1m string around my head at 60rpm requires a different input of energy to a 2kg weight on the same string at the same speed, doesn't it? Or doesn't it?


Eric Mc
77,281 posts
151 months

Once the object has achieved a stable orbit, it will stay in that orbit indefinitely (ignoring any other influences that might affect the object once it is in space).
The energy required to get that object to the stable orbit will have been set by the mass of the object. That is why a 7.5 million pound thrust Saturn V was needed to launch 100 tons into a low earth orbit whereas the much less powerful Atlas was required to put 1.5 tons into the same type of orbit.


BarnatosGhost
7,920 posts
139 months

But why does a 1 ton satellite have a geosynchronous orbit at the same distance as a 2 ton satellite?
Isn't there a difference? It 'feels' like there should be.


MartG
3,831 posts
90 months

BarnatosGhost said: I ask because that doesn't seem intuitive to me. Swinging a 1kg weight on a 1m string around my head at 60rpm requires a different input of energy to a 2kg weight on the same string at the same speed, doesn't it?
Or doesn't it? A string isn't gravity. While swinging a 2kg weight on a string will put more force onto the string than a 1kg one will, gravity 'automatically' puts more force on a 2kg mass than a 1kg one. The two important equations you need to know to work it out are: Force due to gravity F=GMm/r^2 ( G=universal gravitational constant, M=mass of Earth, m=mass of object, d^2=sqaure of the distance between the centre of gravity of the two objects ) 'Centrifugal Force' ( I know, it doesn't really exist ) F=mv^2/r (m=mass of object, v=velocity ( parallel to planet surface ) r=radius of the orbit ) For something to be in a stable orbit the centrifugal force must equal the force due to gravity, so the equations simplify to GM=rv^2 i.e. the radius of the orbit multiplied by the square of the velocity equals the mass of the Earth multiplied by the gravitational constant. Notice that the mass of the satellite doesn't appear in this equation, as it doesn't affect the result


Eric Mc
77,281 posts
151 months

BarnatosGhost said: But why does a 1 ton satellite have a geosynchronous orbit at the same distance as a 2 ton satellite?
Isn't there a difference? It 'feels' like there should be. "Feelings" aren't very scientific.


MartG
3,831 posts
90 months

BarnatosGhost said: But why does a 1 ton satellite have a geosynchronous orbit at the same distance as a 2 ton satellite?
Isn't there a difference? It 'feels' like there should be. If you had two 1 tonne satellites tied together with string, do you think they would be in a different orbit to a 2 tonne satellite ? ( incidentally, it's this concept that Galileo used to show that objects of different mass fall at the same rate )


BarnatosGhost
7,920 posts
139 months

MartG said: BarnatosGhost said: I ask because that doesn't seem intuitive to me. Swinging a 1kg weight on a 1m string around my head at 60rpm requires a different input of energy to a 2kg weight on the same string at the same speed, doesn't it?
Or doesn't it? A string isn't gravity. While swinging a 2kg weight on a string will put more force onto the string than a 1kg one will, gravity 'automatically' puts more force on a 2kg mass than a 1kg one. The two important equations you need to know to work it out are: Force due to gravity F=GMm/r^2 ( G=universal gravitational constant, M=mass of Earth, m=mass of object, d^2=sqaure of the distance between the centre of gravity of the two objects ) 'Centrifugal Force' ( I know, it doesn't really exist ) F=mv^2/r (m=mass of object, v=velocity ( parallel to planet surface ) r=radius of the orbit ) For something to be in a stable orbit the centrifugal force must equal the force due to gravity, so the equations simplify to GM=rv^2 i.e. the radius of the orbit multiplied by the square of the velocity equals the mass of the Earth multiplied by the gravitational constant. Notice that the mass of the satellite doesn't appear in this equation, as it doesn't affect the result Thank you, great answer. That makes sense. Now the crucial testyourunderstanding second question: So if the moon were to be geosynchronous, it too would have to orbit at 37,000 (or whatever the figure was) km?


BarnatosGhost
7,920 posts
139 months

Eric Mc said: BarnatosGhost said: But why does a 1 ton satellite have a geosynchronous orbit at the same distance as a 2 ton satellite?
Isn't there a difference? It 'feels' like there should be. "Feelings" aren't very scientific. If you never intuit that anything seems right or wrong (regardless of whether it is actually right or wrong) I'd suggest that you were unusual... Or did you know exactly what I meant and were 'feeling' a little supercilious?


MartG
3,831 posts
90 months

BarnatosGhost said: So if the moon were to be geosynchronous, it too would have to orbit at 37,000 (or whatever the figure was) km? Yes  well its centre of gravity would be at that distance, but the surface would be nearer.

