Gravity question

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steve-V8s

Original Poster:

2,901 posts

248 months

Saturday 15th August 2015
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This will be simple for someone that has been to school more recently than me.

Whilst sitting in my armchair I am presumably acted on by a force of 1G. If the floor suddenly disappears I and the armchair will accelerate downwards at roughly 64ft per sec/per sec because of the 1G force.

So if I have a G sensor what will it read before and after the floor disappears.

I guess it will read 1G in both cases but in opposite directions.

DocJock

8,356 posts

240 months

Saturday 15th August 2015
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~32 ft/sec/sec, not 64

steve-V8s

Original Poster:

2,901 posts

248 months

Saturday 15th August 2015
quotequote all
DocJock said:
~32 ft/sec/sec, not 64
Yes quite so.

anonymous-user

54 months

Saturday 15th August 2015
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It depends on how the "G" sensor is setup/calibrated.

Dynamic G sensors are typically set up to offset the static gravity component. As such, they read zero G when stationary. This means they can be used to calculate things like vehicle dynamics in all 3 axis on earth. In effect they have a -1g offset in the vertical direction. This will therefore read zero g when you are sat on your chair, peak at 1g as you start to fall, and then return to zero g when you reach terminal velocity


Static G sensors are setup to read the Earths gravity, and so the Z axis will read 1g when sat on your chair, and will read zero g once you get to freefall.

Simpo Two

85,394 posts

265 months

Saturday 15th August 2015
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64ft/sec2 - lay off the pies wink



Eric Mc

121,992 posts

265 months

Saturday 15th August 2015
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If the floor disappears and you start to fall, the G mater will drop to Zero - as you are in free fall. As soon as you stop falling and come to rest, it will register 1G again.

Simpo Two

85,394 posts

265 months

Saturday 15th August 2015
quotequote all
Eric Mc said:
If the floor disappears and you start to fall, the G mater will drop to Zero - as you are in free fall. As soon as you stop falling and come to rest, it will register 1G again.
Although he's be accelerating downwards, as you say I think it will read 0G and not negative. In other words, in a gravitational field you need to accelerate to maintain 0G whereas in space you can just float about...

Edited by Simpo Two on Saturday 15th August 21:39

Eric Mc

121,992 posts

265 months

Sunday 16th August 2015
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No difference. Free falling around the earth and free falling down a lift shaft are the same thing. And you will experience the same floating sensation.

Obviously, with falling down a lift shaft, your floating experience will be a bit shorter than falling around the earth.

turbobloke

103,915 posts

260 months

Sunday 16th August 2015
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Not negative. See 'equivalence principle'. Somebody famous called Albert spoke of "the complete physical equivalence of a gravitational field and a corresponding acceleration of the reference system".

kiseca

9,339 posts

219 months

Sunday 16th August 2015
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A G sensor measures acceleration. While stationary you are not accelerating. When the floor vanishes you will be accelerating downwards at 1G. I would expect the G meter to read accordingly. 0G while sitting, 1G while falling

Eric Mc

121,992 posts

265 months

Sunday 16th August 2015
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What would it read if you are falling around the earth in earth orbit? It's EXACTLY the same as falling on earth.

Falling is falling - whether you hit the ground or miss it.

anonymous-user

54 months

Sunday 16th August 2015
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it's all gone a bit HHGTTG in here now!

anonymous-user

54 months

Sunday 16th August 2015
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anonymous said:
[redacted]
Would Sir like a parrot with his main course?

Moonhawk

10,730 posts

219 months

Sunday 16th August 2015
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Eric Mc said:
What would it read if you are falling around the earth in earth orbit? It's EXACTLY the same as falling on earth.
Something in orbit is not accelerating - it is falling at constant speed - therefore it will read zero.

A g-sensor measures acceleration, so reads positive on acceleration, zero at constant speed (or no speed) and negative on deceleration.

Eric Mc

121,992 posts

265 months

Sunday 16th August 2015
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Is an object falling around the earth (i.e. in orbit) undergoing the same accelerative force as an object falling directly towards the ground?

Would a person in a spacecraft falling around the earth float in the spacecraft (i.e. experience Zero G)

Would a person in a spacecraft falling directly towards the ground also experience Zero G?

kiseca

9,339 posts

219 months

Sunday 16th August 2015
quotequote all
Eric Mc said:
What would it read if you are falling around the earth in earth orbit? It's EXACTLY the same as falling on earth.

Falling is falling - whether you hit the ground or miss it.
0G, because you've got 1G keeping you in orbit vs. 1G acceleration away from Earth due to your tangential velocity. You are in equilibrium. Your rotational speed is keeping you up there and doing the same job as the floor. If you remove the rotational speed from the spaceship, you are no longer in equilibrium and accelerate towards earth at a rate approaching 1G.

If you're sitting on your chair on the second floor you aren't going anywhere because all forces are in equilibrium. No acceleration to measure. The G meter, which measures acceleration, not gravity, should, if it is to be of any use, tell you you are not accelerating. When the floor disappears you are no longer in equilibrium and accelerate downwards. Now, the G - meter should acknowledge your unfortunate predicament by confirming that you are accelerating downwards and are about to have a bad day.

Eric Mc

121,992 posts

265 months

Sunday 16th August 2015
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Will you be floating in your craft as you fall?

What will you, as the occupant, experience?

Vipers

32,876 posts

228 months

Sunday 16th August 2015
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anonymous said:
[redacted]

kiseca

9,339 posts

219 months

Sunday 16th August 2015
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Eric Mc said:
Will you be floating in your craft as you fall?

What will you, as the occupant, experience?
Acceleration towards the earth. Since I'm stiluck in a spaceship, I'll probably feel like I'm floating, but That's relative to the spaceship, not to Earth. Followed shortly by a sudden stop.

If it reads 1G while you're sitting, what will it read when the floor vanishes? Now you're accelerating towards the earth's centre at 9.81m/s^2. which is acceleration due to gravity. 1G. It can't read 1G if that's what it said when you were sitting still, because your state of acceleration has changed. It can't say more than 1G, because you're accelerating due to gravity, the verydefinition of 1G. It can't now say 0G, because it's an accelerometer and I'm now accelerating directly towards the earth.

Eric Mc

121,992 posts

265 months

Monday 17th August 2015
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So it is different.