Ford Focus Mk2 [ST] Estate Sleeper - Build Thread
Discussion
Another quick picture of the car with the surfboards on the roof, and a boot full of stuff again.
Which brings me quite nicely onto the topic of the rear suspension, as brought up by Jack.
As the picture above, the car sits nicely when fully loaded which is about 30mm lower than when empty and then the same ride height as the front end. It still bounces around terribly when it's loaded though!
To try and combat this I have ordered a set of Eibach lowering springs (-30mm) as these are the only estate springs I could find that are actually stuffer, but should also match the ride height of the front springs. This may not be the final solution to the problem, but it's a good starting point.
Despite a lot of suggestions otherwise, there does not seem to be a mk2 estate 'Handling Pack' option on rear dampers, as equipped and non-equipped cars bring up the same rear damper part numbers. Therefore I have selected a set of Sachs rear dampers, nothing special but I don't want to spend a load of money on something as a starting point.
Which brings me quite nicely onto the topic of the rear suspension, as brought up by Jack.
JackP1 said:
Unless i've missed it, have you changed out the rear suspension from the ST or kept the originals on there?
Which as he quite correctly has pointed out is completely Diesel Estate standard. It sits far too high when the car is empty, bounces around compared to the front springs and I think the rear dampers are shot anyway. As the picture above, the car sits nicely when fully loaded which is about 30mm lower than when empty and then the same ride height as the front end. It still bounces around terribly when it's loaded though!
To try and combat this I have ordered a set of Eibach lowering springs (-30mm) as these are the only estate springs I could find that are actually stuffer, but should also match the ride height of the front springs. This may not be the final solution to the problem, but it's a good starting point.
Despite a lot of suggestions otherwise, there does not seem to be a mk2 estate 'Handling Pack' option on rear dampers, as equipped and non-equipped cars bring up the same rear damper part numbers. Therefore I have selected a set of Sachs rear dampers, nothing special but I don't want to spend a load of money on something as a starting point.
Furyjoell said:
It looks so plain and boring in that picture, I absolutely love it, the ride height looks spot on too, in my opinion.
In the picture the boot is fully loaded so that's why it's siting level, that's the ride height I want to achieve when it's empty. But I also want to make it stiffer as the rear is far too soft compared to the front. CHR15 G said:
In the picture the boot is fully loaded so that's why it's siting level, that's the ride height I want to achieve when it's empty. But I also want to make it stiffer as the rear is far too soft compared to the front.
Yeah I know, I was agreeing that that amount of drop when empty would look perfect.neilbauer said:
Furyjoell said:
CHR15 G said:
In the picture the boot is fully loaded so that's why it's siting level, that's the ride height I want to achieve when it's empty. But I also want to make it stiffer as the rear is far too soft compared to the front.
Yeah I know, I was agreeing that that amount of drop when empty would look perfect.Stumbled upon what must be the most absolute, complete opposite to your car.
(Cover your eyes)
http://www.ebay.co.uk/itm/2005-FORD-FOCUS-LX-RS-RE...
(Cover your eyes)
http://www.ebay.co.uk/itm/2005-FORD-FOCUS-LX-RS-RE...
Furyjoell said:
CHR15 G said:
In the picture the boot is fully loaded so that's why it's siting level, that's the ride height I want to achieve when it's empty. But I also want to make it stiffer as the rear is far too soft compared to the front.
Yeah I know, I was agreeing that that amount of drop when empty would look perfect.blueST said:
You could cut the springs as a temporary measure, which would have the duel effects of reducing the ride height and increasing the spring rate. Or is that too bodgetastic for this thread
Not really into chopping springs, and I don't thin that will actually change the spring rate either.pixelatedJH said:
Stumbled upon what must be the most absolute, complete opposite to your car.
(Cover your eyes)
http://www.ebay.co.uk/itm/2005-FORD-FOCUS-LX-RS-RE...
I'm not going to judge, as the person who did that car probably wont understand my car either, but yes-that is the complete opposite!! (they haven't swapped the interior either)(Cover your eyes)
http://www.ebay.co.uk/itm/2005-FORD-FOCUS-LX-RS-RE...
blueST said:
You could cut the springs as a temporary measure, which would have the duel effects of reducing the ride height and increasing the spring rate. Or is that too bodgetastic for this thread
It still takes the same load to deflect the spring one unit of measurement. A 100 N/mm spring (for example) requires 100N load to compress it 1mm.To increase the rate of a (standalone) spring you can produce it from wire of a larger diameter, or coil it with a smaller outer diameter, or fewer active coils.
(Spring rate, when fitted to a vehicle, is dependant on spring-damper angle and wishbone geometry I think though)
Edited by 13aines on Thursday 19th November 20:11
13aines said:
It still takes the same load to deflect the spring one unit of measurement. A 100 N/mm spring (for example) requires 100N load to compress it 1mm.
To increase the rate of a (standalone) spring you can produce it from wire of a larger diameter, or coil it with a larger outer diameter, or fewer active coils.
(Spring rate, when fitted to a vehicle, is dependant on spring-damper angle and wishbone geometry I think though)
I am not recommending cutting springs, but it definitely does increase the rate. I'm not great at explaining stuff, but spring rate is also a function of length of the wire. Think of a straight torsion spring, if you shorten it it gets stiffer, same applies to a coil as it is still torsion that gives the springiness. If you google it there a some far more detailed explanations than I can manage.To increase the rate of a (standalone) spring you can produce it from wire of a larger diameter, or coil it with a larger outer diameter, or fewer active coils.
(Spring rate, when fitted to a vehicle, is dependant on spring-damper angle and wishbone geometry I think though)
blueST said:
13aines said:
It still takes the same load to deflect the spring one unit of measurement. A 100 N/mm spring (for example) requires 100N load to compress it 1mm.
To increase the rate of a (standalone) spring you can produce it from wire of a larger diameter, or coil it with a larger outer diameter, or fewer active coils.
(Spring rate, when fitted to a vehicle, is dependant on spring-damper angle and wishbone geometry I think though)
I am not recommending cutting springs, but it definitely does increase the rate. I'm not great at explaining stuff, but spring rate is also a function of length of the wire. Think of a straight torsion spring, if you shorten it it gets stiffer, same applies to a coil as it is still torsion that gives the springiness. If you google it there a some far more detailed explanations than I can manage.To increase the rate of a (standalone) spring you can produce it from wire of a larger diameter, or coil it with a larger outer diameter, or fewer active coils.
(Spring rate, when fitted to a vehicle, is dependant on spring-damper angle and wishbone geometry I think though)
Wow, you learn something new everyday. I think you were correct all along blueST... I think this is the explanation mathematically, as I was thinking.
Length does not come into the equation for calculating spring stiffness - I thought it did, so assumed that with a linear spring by reducing length you would reduce the number of coils roughly proportionally.
k = spring stiffness
d = wire diameter
G = shear modulus of spring material
D = mean diameter
N = number of active coils
When you cut the springs you reduce the active number of coils and the length. Since length doesn't come into calculating the spring stiffness the only change in the equation for calculating the spring stiffness is a reduction in the number of active coils, which since this is on the denominator increases the spring rate.
Embarrassing! My apologies for doubting you.
Length does not come into the equation for calculating spring stiffness - I thought it did, so assumed that with a linear spring by reducing length you would reduce the number of coils roughly proportionally.
k = spring stiffness
d = wire diameter
G = shear modulus of spring material
D = mean diameter
N = number of active coils
When you cut the springs you reduce the active number of coils and the length. Since length doesn't come into calculating the spring stiffness the only change in the equation for calculating the spring stiffness is a reduction in the number of active coils, which since this is on the denominator increases the spring rate.
Embarrassing! My apologies for doubting you.
Edited by 13aines on Thursday 19th November 20:35
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