Arithmetic problem - brainbox required !
Arithmetic problem - brainbox required !
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Discussion

dibbly_dobbler

Original Poster:

11,492 posts

226 months

Tuesday 2nd December 2008
quotequote all
A brainy chum of mine at work gave me the following problem and I'm stumped !

a,b,c,d are integers. Using no number more than once per calculation and using only addition and subtraction you can get 1 to 40 inclusive. Solve for a,b,c,d

I've had a few goes and failed horribly - help !


Rob.

17,911 posts

247 months

Tuesday 2nd December 2008
quotequote all
42.

HTH.

Snake the Sniper

2,544 posts

230 months

Tuesday 2nd December 2008
quotequote all
Do you have to use a, b, c + d in all equations?

AlpineWhite

2,164 posts

224 months

Tuesday 2nd December 2008
quotequote all
can an integer just be itself

say a=4, could you just say 4=4?

dibbly_dobbler

Original Poster:

11,492 posts

226 months

Tuesday 2nd December 2008
quotequote all
Snake the Sniper said:
Do you have to use a, b, c + d in all equations?
No - just as required.

For instance 7,9,10,14 got me from 1-17 inclusive bit then I got stuck...

TWSTEEL

1,099 posts

218 months

Tuesday 2nd December 2008
quotequote all
Just a thought but as long as it's a whole number it's an integer and it can be a minus number, so sticking a negative integer in doubles its usefulness as when you subtract from a minus number you add to it. idea

mybrainhurts

90,809 posts

284 months

Tuesday 2nd December 2008
quotequote all
I blame global warming...

Shaw Tarse

31,888 posts

232 months

Tuesday 2nd December 2008
quotequote all
Rob. said:
42.

HTH.
yes the answer is 42!

Austin.J

888 posts

221 months

Tuesday 2nd December 2008
quotequote all
mybrainhurts said:
I blame global warming...
Canada is the place to blame...

CrashTD

1,788 posts

233 months

Tuesday 2nd December 2008
quotequote all
TWSTEEL said:
Just a thought but as long as it's a whole number it's an integer and it can be a minus number, so sticking a negative integer in doubles its usefulness as when you subtract from a minus number you add to it. idea
but you can use addition and subtraction

mccarn

641 posts

226 months

Tuesday 2nd December 2008
quotequote all
I've been at the pub tonight so its not making much senselaugh

Edited by mccarn on Tuesday 2nd December 22:09

Titan Simba

18,451 posts

223 months

Tuesday 2nd December 2008
quotequote all
Shaw Tarse said:
Rob. said:
42.

HTH.
yes the answer is 42!
yes The answer is ALWAYS 42!

glencooley

207 posts

234 months

Tuesday 2nd December 2008
quotequote all
Its a fibonacci sequence



CivicMan

2,211 posts

230 months

Tuesday 2nd December 2008
quotequote all
I'm getting -42.

AlpineWhite

2,164 posts

224 months

Tuesday 2nd December 2008
quotequote all
27, 9, 3, 1. I think.

glencooley

207 posts

234 months

Tuesday 2nd December 2008
quotequote all
i thought

1,5,13,21

but yours is better ^^^^

TWSTEEL

1,099 posts

218 months

Tuesday 2nd December 2008
quotequote all
CrashTD said:
TWSTEEL said:
Just a thought but as long as it's a whole number it's an integer and it can be a minus number, so sticking a negative integer in doubles its usefulness as when you subtract from a minus number you add to it. idea
but you can use addition and subtraction
banghead
Of course - what a plonker I am!!!!!

OK so if you start subtracting your larger intergers from your smaller ones you create "new" integers to use in your............wobble

TVR MAN

1,038 posts

251 months

Tuesday 2nd December 2008
quotequote all
I'm still checking this but my guess is 1,3,5,7.

It's fine up to 23 so far.

AlpineWhite

2,164 posts

224 months

Tuesday 2nd December 2008
quotequote all
Using only addition and subtraction! I'm not sure how you're going to get past 16 fella.

glencooley

207 posts

234 months

Tuesday 2nd December 2008
quotequote all
TVR MAN said:
I'm still checking this but my guess is 1,3,5,7.

It's fine up to 23 so far.
You can only use addition and subtraction......added all together they dont make 23???


confused