Prove no square number ends in an 8
Discussion
If you write down the first ten numbers, and their squares, you see that they end in:
1, 4, 9, 6, 5, 6, 9, 4, 1, 0.
Carry on, and they carry on with that pattern (11 squared is 121, 21 squared is 441, 31 squared is 961...)
So, square numbers can only ever end with one of these numbers (the 'proof' bit is that the 'units' of the square is always the product of two numbers under 10)
That may help.....
Jon
1, 4, 9, 6, 5, 6, 9, 4, 1, 0.
Carry on, and they carry on with that pattern (11 squared is 121, 21 squared is 441, 31 squared is 961...)
So, square numbers can only ever end with one of these numbers (the 'proof' bit is that the 'units' of the square is always the product of two numbers under 10)
That may help.....

Jon
Something is coming back to me: Have you tried using proof by induction?
Unfortunately all my best work is done by 12:00, its all downhill from lunchtime onwards.
ETA: jon.nic is inferring the same thing. If you prove it for P(n) = k and also for P(n) = k + 1 then it must be true for every integer value of n.
Unfortunately all my best work is done by 12:00, its all downhill from lunchtime onwards.
ETA: jon.nic is inferring the same thing. If you prove it for P(n) = k and also for P(n) = k + 1 then it must be true for every integer value of n.
Edited by Geoff82 on Tuesday 10th February 18:34
KatieK said:
Any number can be written like
n = 10a + b
where b is between 0 and 9
So if you square it you get
n2 = 100a2 + 20ab + b2 where 2 is square symbol
so n2 has the same last digit as b2. If you square 0 to 9 you can see the last digit in the square of a number must end in 0,1,4,5,6 or 9
Egad, I believe she's got it! KatieK in 'not posting sn = 10a + b
where b is between 0 and 9
So if you square it you get
n2 = 100a2 + 20ab + b2 where 2 is square symbol
so n2 has the same last digit as b2. If you square 0 to 9 you can see the last digit in the square of a number must end in 0,1,4,5,6 or 9
te' shocker!scorp said:
10 Pence Short said:
Ask KatieK, she's good with maths.
KatieK said:
Any number can be written like
n = 10a + b
where b is between 0 and 9
So if you square it you get
n2 = 100a2 + 20ab + b2 where 2 is square symbol
so n2 has the same last digit as b2. If you square 0 to 9 you can see the last digit in the square of a number must end in 0,1,4,5,6 or 9
owned. n = 10a + b
where b is between 0 and 9
So if you square it you get
n2 = 100a2 + 20ab + b2 where 2 is square symbol
so n2 has the same last digit as b2. If you square 0 to 9 you can see the last digit in the square of a number must end in 0,1,4,5,6 or 9

I'm off to spend a few hours self flagellating for my insolence.
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makes sense to me.