Maths problem

[Robmarriott]

I've tried to solve this but I'm not sure I've done it right...

We currently work every other Saturday, 3 people on one, 3 on the other.

The company is trying to go to 1 in 3 Saturdays but we'd need an extra person in the team as we can't function with less than 3 of us here.

Anyway, for now, my manager has suggested we take the official line of 1 in 3 but continue to work every other and we'd get paid overtime for the ones we shouldn't be working.

I can't for the life of me work out how many out of the 26 would be paid overtime though?

Can anyone work it out? I'm sure it's simple but I've not had to work mathsy stuff out for well over 15 years.

[Gary29]

It's late in the day and I'm tired, but I think you're looking at somewhere in the region of 9 paid at overtime and 17 at your normal rate.

[LeoSayer]

Official line is 17.3 Saturdays ie. 26/3*2

Overtime is 8.7 Saturdays ie. 26/3*1

[Doofus]

If you officially work 1 in 3, then you officially work 8.7 weeks out of 26. Call it 9.

If you actually work 1 in 2, then you actualy work 13 weeks out of 26.

Therefore 4 of them are overtime. (13-9)

[Robmarriott]

LeoSayer said:

Official line is 17.3 Saturdays ie. 26/3*2

Overtime is 8.7 Saturdays ie. 26/3*1

See, I've got it at this but in reverse.

If I'm working every other weekend but should only be working every third, there's one occasion in every 6 week period when I'm working and should be, 2 in every 6 weeks where I'm working and shouldn't, which is the important one (plus 1 when I'm not working but should be)

I make it 17 (or 18, depending how it falls) overtime, 9 (or 8) standard pay.

[Mammasaid]

Correct, it will be 17 rounded to the nearest whole number.

it's rounded as 52 (weeks in a year) divided by 3 isn't an integer.

[T1547]

Maybe easy way to think of it is for every six week period you will work 2 official and 1 overtime.

Multiply up the six week periods to your required total, job done