Show your working… come on eggheads.

[The Rotrex Kid]

I’ve been asked to solve this.



You can Google the answer, which is 4C6 --> 5E1 --> 7A7 --> 3C8 --> 5Y9 --> 3A1 --> 2H2 but HOW? I can’t just stick the answer down without knowing how. Any smart arses work it out?

[Getragdogleg]

I'm posting so I can keep an eye on this thread.

Not solved it yet.

[ten200]

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

[The Rotrex Kid]

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

It passes the sniff test! Any advances on this?

[ILikeCake]

I hate these questions. Mainly because I never get them, and partly because there must be an infinite number of answers. The real question is 'guess the arbitrary continuation of this sequence'.

Those numbers could relate to anything. Substitutions? Coordinates? Chapters in some obscure Welsh poem?

[Doofus]

The Rotrex Kid said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

It passes the sniff test! Any advances on this?

That only works for the first two circles. It doesn't get you from E to A

[RacingPete]

Doofus said:

That only works for the first two circles. It doesn't get you from E to A

1-5 + E(5) gets to A
Now if they hadn’t drawn the line up the first A it would be tough.

[The Rotrex Kid]

Doofus said:

The Rotrex Kid said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

It passes the sniff test! Any advances on this?

That only works for the first two circles. It doesn't get you from E to A

1-5 = -4, E-4=A

[Dixy]

Mornington Crescent

[cml24]

The Rotrex Kid said:

Doofus said:

The Rotrex Kid said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

It passes the sniff test! Any advances on this?

That only works for the first two circles. It doesn't get you from E to A

1-5 = -4, E-4=A

Seems reasonable!

[Wacky Racer]

Mathematics is bunk.

[Doofus]

cml24 said:

The Rotrex Kid said:

Doofus said:

The Rotrex Kid said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

It passes the sniff test! Any advances on this?

That only works for the first two circles. It doesn't get you from E to A

1-5 = -4, E-4=A

Yes, and then what?

Seems reasonable!

[OzzyR1]

Wacky Racer said:

Mathematics is bunk.

Aye, must be 30+ years since I was at school and were told that if we didn't understand Pythagoras or the more difficult calculus, that would be us on the scrap-heap in terms of job opportunities.

Couldn't even have a calculator in exams - we were told that there is no chance you will ever be in a situation where you will have a pocket calculator to pull out in times of difficulty in the future so you may as well learn to use the tables;, sine, cosine etc.

30 years later, we aren't carrying a calculator but a piece of kit unfathomable at the time - phones now are essentially the Hitchhiker's Guide

[OzzyR1]

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

Also, this person is correct.

[Doofus]

OzzyR1 said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

Also, this person is correct.

How do you get from E to A? And then from A to Y?

It's not correct. At least, not without additional goalpost movements.

[The Rotrex Kid]

Doofus said:

OzzyR1 said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

Also, this person is correct.

How do you get from E to A? And then from A to Y?

It's not correct. At least, not without additional goalpost movements.

You’re welcome to suggest an alternative answer?

[Doofus]

The Rotrex Kid said:

Doofus said:

OzzyR1 said:

ten200 said:

I think the answer you've found on google is wrong, and the correct answer is 4C6, 5E1, 7A7, 3A1, 5Y9, 3C8, 2H2.


In each circle, subtract the 2nd number from the 1st. That number gives you the number of letters in the alphabet between the letter in this circle and the letter in the next circle. eg. 4C6; 6-4=2, C + 2 places =E, so the 2nd pattern will be the one with an E in it.

Also, this person is correct.

How do you get from E to A? And then from A to Y?

It's not correct. At least, not without additional goalpost movements.

You’re welcome to suggest an alternative answer?

I don't have one, but that answer is demonstrably not correct.

Just because it's the only suggested solution doesn't make it right.

[The Rotrex Kid]

Doofus said:

How do you get from E to A? And then from A to Y?

5E1

1-5 = -4, E+ -4 = A

There are then 2 with A in the middle. The 7A7 keeps you on A so use that one first, then the next A is 3A1, 1-3 = -2. A+ -2 = Y so 5Y9, 9-5 = 4. Y+4 = C, so 3C8, 8-3 = 5, C+5 = H.

Checks out for me.

Edited by The Rotrex Kid on Saturday 20th November 08:48

[Doofus]

The Rotrex Kid said:

Doofus said:

How do you get from E to A? And then from A to Y?

5E1

1-5 = -4, E+ -4 = A

There are then 2 with A in the middle. The 7A7 keeps you on A so use that one first, then the next A is 3A1, 1-3 = -2. A+ -2 = Y so 5Y9, 9-5 = 4. Y+4 = C, so 3C8, 8-3 = 5, C+5 = H.

Checks out for me.

Edited by The Rotrex Kid on Saturday 20th November 08:48

Ok, fair enough.

[The Rotrex Kid]