A simple maths question.

[Munter]

You have a two 2 seat sports cars. You and the Wife need to drive 2 children to different schools. Both journeys take exactly 10 minutes. Which means from start to finish you are busy for 10 minutes.

You sell both cars and the Wife into slavery. With the profits you buy one 2 seat sports car that can travel at twice the speed on these journeys, thus halving the time taken. You drive both children to school from start to finish in the same 10 minutes.

What is your average "child delivery time" for both situations?

Edited by Munter on Thursday 26th November 12:08

[mattviatura]

9 months

[Don]

Are the schools in exactly opposite directions and does the other child ride for the whole journey or just get in once the first has been delivered?

[Munter]

mattviatura said:

9 months

Oh very good. Perhaps I could have chosen a better phrase.

There's no trick to this one. It's turned into a bit of a plane / belt conversation and I thought I'd see if PHers are smart or not....

[Munter]

Don said:

Are the schools in exactly opposite directions and does the other child ride for the whole journey or just get in once the first has been delivered?

Both scenarios the cars have only 2 seats. So you have to return home to pick up the 2nd child

[youngsyr]

Edited as included average return trip first time around.

The answer is 5 minutes for the first and 2.5 minutes for the second.

"Child delivery" is half of the average total busy time, not total average return trip.

Edited by youngsyr on Thursday 26th November 12:22

[Jgtv]

5 minutes.

But you should be more worried about leaving the 2nd child unattended there are pedos everywhere the newspapers told me!

[evenflow]

Is the sports car a TVR? If so, 4 hours 12 minutes.

[Geezer-20v]

Assuming in the first scenario it takes 10 minutes from home to the school, then in the second scenario surely it's:-

Home to 1st School - 5mins

1st School to Home - 5mins

Home to 2nd School - 5mins


So 15mins in total to complete the dropping off.

[f-fuxake]

Don't forget to factor in half an hour for getting pulling by the police for doing sixty past a school!

[Munter]

youngsyr said:

Edited as included average return trip first time around.

The answer is 5 minutes for the first and 2.5 minutes for the second.

"Child delivery" is half of the average total busy time, not total average return trip.

Edited by youngsyr on Thursday 26th November 12:22

And this is what we found to be the conclusion. The more people think about it the more answers they come up with.

But I'm saying the answer is 5 minutes in both scenarios.

A)Both children ready 07:30. Both delivered by 07:35. Average 5 mins.
B)Both children ready 07:30. 1st delivered by 07:32:30, 2nd delivered by 07:37:30. Average 5 mins. (2.5 + 7.5 / 2 = 5)

Seems a few people count the return journey in the delivery time of the 2nd child and come up with an average of 7.5.

Now to me delivery time is from when something is ready to when it's at it's destination. Not when the messenger gets home...

Edit: To avoid 88 mph time travel effect...

Edited by Munter on Thursday 26th November 13:02

[Hugo a Gogo]

Munter said:

B)Both children ready 07:30. 1st delivered by 07:32:30, 2nd delivered by 07:27:30. Average 5 mins. (2.5 + 7.5 / 2 = 5)

is it a DeLorean?

[WorAl]

Hugo a Gogo said:

Munter said:

B)Both children ready 07:30. 1st delivered by 07:32:30, 2nd delivered by 07:27:30. Average 5 mins. (2.5 + 7.5 / 2 = 5)

is it a DeLorean?

Alright there Doc?

[Munter]

Hugo a Gogo said:

Munter said:

B)Both children ready 07:30. 1st delivered by 07:32:30, 2nd delivered by 07:27:30. Average 5 mins. (2.5 + 7.5 / 2 = 5)

is it a DeLorean?

bks. I knew I'd get this wrong somewhere!

[Menguin]

Surely if both journeys take 10 minutes originally, that is 5 minutes there, 5 minutes back?

1st child is delivered in 2.5 minutes.

It takes you 2.5 minutes to get home, child jumps through moving window into spare seat, you take 2.5 minutes to get to second destination, with another 2.5 minutes to get home.

Depending on your definition of child delivery time - is it from the child's point of view?

If it is from your point of view, it takes 2.5 minutes to deliver 1st child, and 5 minutes to deliver the second, provided you are counting from when you drop off child 1.

So average child delivery time would be 2.5 + 5 /2

Edited by Menguin on Thursday 26th November 13:21

[Lost_BMW]

This is an interesting (or uninteresting depending on pov) related one . .

Cyril cycles to his friend’s house at 30 km/h and returns back at 20 km/h – what was his average speed?

[louiebaby]

Lost_BMW said:

This is an interesting (or uninteresting depending on pov) related one . .

Cyril cycles to his friend’s house at 30 km/h and returns back at 20 km/h – what was his average speed?

24 km/h

[WorAl]

louiebaby said:

Lost_BMW said:

This is an interesting (or uninteresting depending on pov) related one . .

Cyril cycles to his friend’s house at 30 km/h and returns back at 20 km/h – what was his average speed?

26.0869565217 km/h

[louiebaby]

WorAl said:

louiebaby said:

Lost_BMW said:

This is an interesting (or uninteresting depending on pov) related one . .

Cyril cycles to his friend’s house at 30 km/h and returns back at 20 km/h – what was his average speed?

26.0869565217 km/h

Oi you bugger, stop making me look silly!

[King Herald]

Munter said:

You have a two 2 seat sports cars. You and the Wife need to drive 2 children to different schools. Both journeys take exactly 10 minutes. Which means from start to finish you are busy for 10 minutes.

You sell both cars and the Wife into slavery. With the profits you buy one 2 seat sports car that can travel at twice the speed on these journeys, thus halving the time taken. You drive both children to school from start to finish in the same 10 minutes.

What is your average "child delivery time" for both situations?

I don't know. We only have one child.