Question for the mathematicians
Discussion
OK, struggling with this one a little so need some back up.
You have a box sitting on a flat surface.
You lift one edge up 5 degrees (two corners off the floor).
You then lift one other corner off the floor by 5 degrees. So you now have two corners at a known height from the floor and another (the furthest from the point on the floor) at a random height.
How do you work out the height of the unknown corner and what angle that point is in relation to the floor?
I hope my illustration helps, explain.
What is H and what is alpha? thank you PH
ETA, is alpha still 5 degrees?

You have a box sitting on a flat surface.
You lift one edge up 5 degrees (two corners off the floor).
You then lift one other corner off the floor by 5 degrees. So you now have two corners at a known height from the floor and another (the furthest from the point on the floor) at a random height.
How do you work out the height of the unknown corner and what angle that point is in relation to the floor?
I hope my illustration helps, explain.
What is H and what is alpha? thank you PH
ETA, is alpha still 5 degrees?

Edited by WorAl on Tuesday 14th September 12:14
From your picture, H = 10 + 20 = 30 and I'd find alpha from tan^-1(H / sqrt(l^2+w^2)) where l and w are the length and width respectively. If you like a combination of trig and algebra you can probably get it to a cleaner answer, given that as you've drawn it, l is 20/sin 5 and w is 10/sin 5 so l = 2w.
If you need a proof - think in terms of two orthogonal vectors. Effectively you're raising the whole of the back line of the box by 10 then rotating it by 5 degrees at 90 degrees to the original lift, so effectively the height H is l sin 5 + w sin 5...
ETA... if you're a design engineer, why do you need to ask the mathematicians of PH for this?
If you need a proof - think in terms of two orthogonal vectors. Effectively you're raising the whole of the back line of the box by 10 then rotating it by 5 degrees at 90 degrees to the original lift, so effectively the height H is l sin 5 + w sin 5...
ETA... if you're a design engineer, why do you need to ask the mathematicians of PH for this?
Edited by StressedDave on Tuesday 14th September 12:27
StressedDave said:
ETA... if you're a design engineer, why do you need to ask the mathematicians of PH for this?
It's an argument we're having in the office. If I didn't have such a s
tty CAD system it could have been solved in 2 seconds by actually drawing it out in 3D.Just trying to settle it with external sources that's all.
Roll your eyes all you like, when there are 3 people arguing a point and they all have different points of view, how do you argue that you're right, even if you do perform calculations for them (when they are performing calculations for their "theory") without having external sources or physically drawing the thing out?


Edited by WorAl on Tuesday 14th September 12:54
I'm disgusted with you WorAl. You've sullied the name of design engineers the world over. You should be ashamed. Get out! Hang up your cardigan, retract your propelled pencil and take your tupperware lunch-box with you. Never darken these hallowed doors again.
Seeing as this particular thread is mainly inhabited by engineers, I should point out that I was being sarcastic. Also, I don't actually know whether he has any of the items listed with which to take as he leaves. Finally, I realise that it would be physically very difficult for a lone human of typical dimensions to darken a door enough to justify the state of "being darkened". Thank you.
Famous Graham said:
Hang on...by lifting the third corner, you'll lower the opposite one and raise the one in between them.
So the "first edge" corners will have changed and alpha will be 5.
Not if you maintain that first angle; as in my comment above. The long front edge becomes a 'hinge' as the second lift occurs.So the "first edge" corners will have changed and alpha will be 5.
O/T: Did the book arrive ok?
WorAl said:
You then lift one other corner off the floor by 5 degrees.
Should have beenWorAl said:
You then lift one other corner off the floor and adjust until the original corners are still at 5 degrees. What are H and alpha
If it had been worded correctly, I'd have got it straight off. No need for calculators or anything.Note : May not be true
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, certainly not for sub A-level stuff like that. As for needing a CAD system to prove it...



