Exhaust gas volumetric rate

[greeer]

Hello!

Does anyone know the approximate maximum exhaust gas volumetric flow rate of a regular diesel engine?
I am talking about a Ford 1.5-2L not any 4.8L monster or something.

Thanks!

[bolide]

Cylinder volume x number of firing cycles @ max rpm x volume uplift for combustion / seconds?

I would expect the volume of exhaust gas will exceed the cylinder volume as combustion will generate more volume. But that factor should be Googleable

Nick Froome

[AW111]

Exhaust gas volume is approx. capacity x revs x VE x expansion.
2l engine @4500 rpm = 75 litres / sec nominal intake air.

Assume VE of 0.95
Exhaust temp of 850 C (at the head) so expansion of (850+273) / (20+273), or around 3.7 (assuming no back pressure)

So my back-of-envelope says around 200-250 litres / sec.

I await Max_Torque or another qualified engineer telling me how wrong I am, and why

Edit - I forgot to allow for water vapour (product of combustion), so my numbers are probably bks

Edited by AW111 on Thursday 22 March 11:46

[greeer]

AW111 said:

Exhaust gas volume is approx. capacity x revs x VE x expansion.
2l engine @4500 rpm = 75 litres / sec nominal intake air.

Assume VE of 0.95
Exhaust temp of 850 C (at the head) so expansion of (850+273) / (20+273), or around 3.7 (assuming no back pressure)

So my back-of-envelope says around 200-250 litres / sec.

I await Max_Torque or another qualified engineer telling me how wrong I am, and why

Edit - I forgot to allow for water vapour (product of combustion), so my numbers are probably bks

Edited by AW111 on Thursday 22 March 11:46

This cannot be serious, do you realise how large is 200L per second?

Here it shows that normally it's 2.5m3/min which is 2500L/min which is 42L/second.

http://www.sokken.co.jp/files/products/AirFlowmete...

But again it looks huge. It is from a 4.8L engine. I need for 2.0L maximum, should I assume half of it?

[GreenV8S]

AW111 said:

Exhaust gas volume is approx. capacity x revs x VE x expansion.
2l engine @4500 rpm = 75 litres / sec nominal intake air.

Times half, if it's a four-stroke.

[AW111]

GreenV8S said:

AW111 said:

Exhaust gas volume is approx. capacity x revs x VE x expansion.
2l engine @4500 rpm = 75 litres / sec nominal intake air.

Times half, if it's a four-stroke.

I did that. 4500 rpm is 75 revs / sec, times 1 litre (2 litres / 2)