Maths question.
Discussion
My rough, old, unexercised and out of date maths schooling tells me this is a question about torque.
The bar, if uniform, weighs an equivalent of 552lb at its mid point. The end that stays on the ground becomes the centre around which the torque acts. Torque is perpendicular force * distance from the centre. If you lift at the other end (not the one that will remain on the ground), you double the distance therefore halve the force, so you have exerted whatever force is equivalent to half of 552lb (i.e. 276 lb) to lift that end of the bar. As the angle of the bar changes, the force due to gravity produced by the weight of the bar moves away from perpendicular. Thus the perpendicular component that you are trying to overcome reduces as the bar rotates towards vertical. The highest the force gets, then, is when you initially lift one end from the ground, and that will be equivalent to lifting 276lb. If you try to lift the bar at its midpoint instead of at one end, even just to lift one end off the ground, you will need to muster the full 552lbs worth of effort.
Maybe
The bar, if uniform, weighs an equivalent of 552lb at its mid point. The end that stays on the ground becomes the centre around which the torque acts. Torque is perpendicular force * distance from the centre. If you lift at the other end (not the one that will remain on the ground), you double the distance therefore halve the force, so you have exerted whatever force is equivalent to half of 552lb (i.e. 276 lb) to lift that end of the bar. As the angle of the bar changes, the force due to gravity produced by the weight of the bar moves away from perpendicular. Thus the perpendicular component that you are trying to overcome reduces as the bar rotates towards vertical. The highest the force gets, then, is when you initially lift one end from the ground, and that will be equivalent to lifting 276lb. If you try to lift the bar at its midpoint instead of at one end, even just to lift one end off the ground, you will need to muster the full 552lbs worth of effort.
Maybe

Edited by Alfanatic on Tuesday 3rd December 20:35
LOL at this thread.
I have a question.
Two cars are travelling at 50mph one is in a vacuum one isn't which one travels further in exactly one hour?! I think it's something to do with drag.
So many wind up threads on here of late it's genuinely hard to know sometimes if people are being a bit thick or actually haven't got a clue. This is what you would call a rhetorical question as it implies an answer is needed when it's in the dam question!
I have a question.
Two cars are travelling at 50mph one is in a vacuum one isn't which one travels further in exactly one hour?! I think it's something to do with drag.So many wind up threads on here of late it's genuinely hard to know sometimes if people are being a bit thick or actually haven't got a clue. This is what you would call a rhetorical question as it implies an answer is needed when it's in the dam question!
Edited by iloveboost on Tuesday 3rd December 21:07
balls-out said:
A Newton is a measure of force, not weight.
Weight is a force. If the OP actually wanted the equivalent mass, I'd sort of assumed he could divide by two himself.

If he wanted the actual mass he'd lifted, the answer is of course 522lbs but on average he'd lifted it by half the height that he'd lifted the end of the bar by (if that makes sense).
Edited by kambites on Tuesday 3rd December 21:06
iloveboost said:
LOL at this thread.
I have a question.
Two cars are travelling at 50mph one is in a vacuum one isn't which one travels further in exactly one hour?! I think it's something to do with drag.
So many wind up threads on here of late it's genuinely hard to know sometimes if people are being a bit thick or actually haven't got a clue.
Being cars, vacuum or not it seems reasonable to assume they are on a road. In which case the one travelling in air travels further. The engine in the car in the vacuum stops due to lack of oxygen and the rolling resistance of the wheels and drivetrain slow the car down.I have a question.
Two cars are travelling at 50mph one is in a vacuum one isn't which one travels further in exactly one hour?! I think it's something to do with drag.So many wind up threads on here of late it's genuinely hard to know sometimes if people are being a bit thick or actually haven't got a clue.

Alfanatic said:
Being cars, vacuum or not it seems reasonable to assume they are on a road. In which case the one travelling in air travels further. The engine in the car in the vacuum stops due to lack of oxygen and the rolling resistance of the wheels and drivetrain slow the car down.

Hehe I like that you picked up that it was a double trap. 

kambites said:
balls-out said:
A Newton is a measure of force, not weight.
Weight is a force. If the OP actually wanted the equivalent mass, I'd sort of assumed he could divide by two himself.

If he wanted the actual mass he'd lifted, the answer is of course 522lbs but on average he'd lifted it by half the height that he'd lifted the end of the bar by (if that makes sense).
Edited by kambites on Tuesday 3rd December 21:06

Alfanatic said:
Being cars, vacuum or not it seems reasonable to assume they are on a road. In which case the one travelling in air travels further. The engine in the car in the vacuum stops due to lack of oxygen and the rolling resistance of the wheels and drivetrain slow the car down.

I misread the original question as being about cats
I hadn't got a f
king clue tbh 
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