Shamefully simple algebra question...

[Landlord]

OK, given the formula;

z = (x-y)/x

Can someone rearrange the equation to find x. Thanks!

no points for drawing an arrow at x and saying here it is.

[Wacky Racer]

If it's so simple why don't you know the answer?...

See me after school.

[Established 1984]

opps rushed it,

x = -y/(z-1)

Edited by Established 1984 on Tuesday 10th November 18:11

[J-c]

Not good at this but is it a 2 ?

[DrTre]

x = not things that Ewan S will be getting any time soon.


(kidding ES, ignore the nay sayers and do your own thang)

[Pesty]

z = (x-y)/x


A complete div at math but I'll have a guess for you lot to laugh at

x= (x+y)*z

[evenflow]

Landlord said:

OK, given the formula;

z = (x-y)/x

Can someone rearrange the equation to find x. Thanks!

no points for drawing an arrow at x and saying here it is.

z = (x-y)/x
zx = (x-y)
zx + y = x
z+y = 1

ETA: Oops, missed the bit about finding x. My answer doesn;t really help.

Edited by evenflow on Tuesday 10th November 18:26

[S6PNJ]

Don said:

Landlord said:

OK, given the formula;

z = (x-y)/x

Can someone rearrange the equation to find x. Thanks!

OK. First multiply each side by x.

zx = x - y

Then add y to each side

zx + y = x

Therefore

x = zx + y



Errrm. Why do you ask?

so finishing this off
subtract zx from each side

x - zx =y

factor out x

x(1-z) = y

divide both sides by (1-z)

x = y/(1-z)

[Landlord]

Wacky Racer said:

If it's so simple why don't you know the answer?...

See me after school.

See the "shameful" bit!

[S6PNJ]

What happened to Don's answer?

[Landlord]

S6PNJ said:

Don said:

Landlord said:

OK, given the formula;

z = (x-y)/x

Can someone rearrange the equation to find x. Thanks!

OK. First multiply each side by x.

zx = x - y

Then add y to each side

zx + y = x

Therefore

x = zx + y



Errrm. Why do you ask?

so finishing this off
subtract zx from each side

x - zx =y

factor out x

x(1-z) = y

divide both sides by (1-z)

x = y/(1-z)

Nice one... thank you!

Jeesh, I didn't realise my maths had got so bad.

[Don]

Established 1984 said:

opps rushed it,

x = -y/(z-1)

That's what I got...after having been an idiot.

[bonsai]

S6PNJ said:

What happened to Don's answer?

He deleted it because x = zx + y doesnt actually let someone solve for x - since x is on both sides.

Which is what I did also....

[Don]

S6PNJ said:

What happened to Don's answer?

I hadn't finished the bloody thing. When I realised I thought "hang on"...do it again and finish it.

[Don]

bonsai said:

S6PNJ said:

What happened to Don's answer?

He deleted it because x = zx + y doesnt actually let someone solve for x - since x is on both sides.

Which is what I did also....

Exactly so.

[jet_noise]

Dear Landlord,

Don said:

Landlord said:

OK, given the formula;

z = (x-y)/x

Can someone rearrange the equation to find x. Thanks!

OK. First multiply each side by x.

zx = x - y

Then add y to each side

zx + y = x

Therefore

x = zx + y



Errrm. Why do you ask?

Don starts on the right lines but if you need to find x then you need x and only x on one side thus:
zx = x - y, then gathering terms with x
zx-x=-y, then taking x out
x(z-1)=-y, then divide both sides by x's multiplier

tarra, roll on the drums, /Paul Daniels it's magic //Paul Daniels
x=-y/(z-1)

regards,
Jet

[maser_spyder]

bonsai said:

I got:

x = (x-y)/z

Me too.

So then multiply both sides by z;

zx = x-y

then subtract x from each side;

zx-x = -y

factorise to get;

x(z-1) = -y

divide both sides by (z-1);

x = -y/(z-1)

Edited by maser_spyder on Tuesday 10th November 18:37

[johnnywgk]

[sunbeam_alpine]

I F N N E X

[james_tigerwoods]

SOHCAHTOA