Any Calculus Experts out there? Integration Advice Needed
Discussion
Right, I'm doing some work for my calculus course at uni, and we're on to integration. The question I'm stuck on involves area. It says
"Find the areas of the regions enclosed by the given curves"
Part A gives the curve y=5-5x^(2/3) and the lines y=0, x=-1 and x=8. Simples, I just integrate y between -1 and 8. Part B is a little more tricky, it just gives the equations of two curves; y=x^3 and y=3x^2; no x limits to integrate between. Am I best off drawing the two curves out and finding out the limits myself, or is there an easier way? I see that x^3 is the integral of 3x^2, this sounds like standard patterns which we learnt in A Level. Or is it even simpler than that, and I just use the straight lines given in part A? Unlikely but I've been given no more information, what I've written here is what I have.
The answer is probably staring me straight in the face, but for some reason I just can't see it. Any help is greatly appreciated, virtual pints to anyone with the right answer.
"Find the areas of the regions enclosed by the given curves"
Part A gives the curve y=5-5x^(2/3) and the lines y=0, x=-1 and x=8. Simples, I just integrate y between -1 and 8. Part B is a little more tricky, it just gives the equations of two curves; y=x^3 and y=3x^2; no x limits to integrate between. Am I best off drawing the two curves out and finding out the limits myself, or is there an easier way? I see that x^3 is the integral of 3x^2, this sounds like standard patterns which we learnt in A Level. Or is it even simpler than that, and I just use the straight lines given in part A? Unlikely but I've been given no more information, what I've written here is what I have.
The answer is probably staring me straight in the face, but for some reason I just can't see it. Any help is greatly appreciated, virtual pints to anyone with the right answer.
kazste said:
looking at where you live are you by any chance attending loughborough college on hnc electrical/engineering course? question is the same as i am trying to answer!
Thats a hnc electrical engineering question?! Jesus, i was thinking of doing that course next year until i read that!
working class said:
kazste said:
looking at where you live are you by any chance attending loughborough college on hnc electrical/engineering course? question is the same as i am trying to answer!
Thats a hnc electrical engineering question?! Jesus, i was thinking of doing that course next year until i read that!
moosepig said:
The curves y=x^3 and y=3x^2 intersect at x=0 and x=3 so presumably those are your limits.
Cheers, virtual pint to you! 
kazste said:
looking at where you live are you by any chance attending loughborough college on hnc electrical/engineering course? question is the same as i am trying to answer!
Nope, I'm actually at Aberdeen University (forgot to update my profile!) studying Mathematics and Engineering, I believe that we have a very similar course though, most of our engineering courses have a common first year.No problem just thought if you was then looking at your wish for a nice car was going to offer to scare you in the elise!!
Don't suppose you have done how to work out angular deflection have you? Can't remember the formula for the life of me I have the diameter and length of the rod the shear stress and the shear modulus. Can work out how to get the second moment of inertia but stuck after that. Any help greatly apreciated!
Don't suppose you have done how to work out angular deflection have you? Can't remember the formula for the life of me I have the diameter and length of the rod the shear stress and the shear modulus. Can work out how to get the second moment of inertia but stuck after that. Any help greatly apreciated!
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