Maths Question

[elster]

I have a question that I can't seem to do.

Can someone explain how to Integrate :



For the first one, it is just the root x + 2x over the x squared. I know with 1/x^2 it would be Ln, but what about with the root x + 2x.

As for the second one, the section with the v I don't know what it means.

Edited by elster on Monday 17th May 18:55

[toasty]

potato

[elster]

toasty said:

potato

I tried the magic 8 ball, I never thought about a potato. Good idea batman.

[43034]

Sorry I can't be of any help, but wondering is this A-level work or higher?

Ta.

[elster]

43034 said:

Sorry I can't be of any help, but wondering is this A-level work or higher?

Ta.

A-Level, as I'm doing foundation year at University.

[MoleVision]

elster said:

I have a question that I can't seem to do.

Can someone explain how to Integrate :



For the first one, it is just the root x + 2x over the x squared. I know with 1/x^2 it would be Ln, but what about with the root x + 2x.

As for the second one, the section with the v I don't know what it means.

Edited by elster on Monday 17th May 18:55

for the 1st one.. err no.6. you need to use proportional integration (i think - its called something like that) where you split it into 2 halves.. one half being 1/X^2.

The 2nd one , no.7 I would assume that you can treat anything that isnt 'squiggle' as a constant which makes it a lot easier.

someone will proabbly be along in a sec to tell me I've forgotten everything I learnt at school and Uni (which are both a few years ago now!)

[james_gt3rs]

You can re-write the equation as:

(x^-3/2) + (2x^-1).

Then it is easy to integrate from there.

I don't recognise the symbols on the second question though.

[elster]

MoleVision said:

elster said:

I have a question that I can't seem to do.

Can someone explain how to Integrate :



For the first one, it is just the root x + 2x over the x squared. I know with 1/x^2 it would be Ln, but what about with the root x + 2x.

As for the second one, the section with the v I don't know what it means.

Edited by elster on Monday 17th May 18:55

for the 1st one.. err no.6. you need to use proportional integration (i think - its called something like that) where you split it into 2 halves.. one half being 1/X^2.

The 2nd one , no.7 I would assume that you can treat anything that isnt 'squiggle' as a constant which makes it a lot easier.

someone will proabbly be along in a sec to tell me I've forgotten everything I learnt at school and Uni (which are both a few years ago now!)

Ah so the first one replace the top line with u, integrate in terms of u.

As for the second one, how would I do that?

[james_gt3rs]

Hang on, just checked Wolfram alpha, comes up with something different, so I may be wrong.

http://www.wolframalpha.com/input/?i=integrate+%28...

[CobolMan]

elster, for the first one split it up into 2 expressions, each of which is divided by x-squared. If I'm right, you should end up with
2 - √2 + 2ln2

Not sure about the second one, I'll see if I can figure out some pointers for you.

Edited to correct the √2 bit

Edited by CobolMan on Monday 17th May 20:37

[navier_stokes]

The second one you only have to integrate with respect to Zeta.... treat everything else as constants. It's easier than the first

[Dixie68]

43034 said:

Sorry I can't be of any help, but wondering is this A-level work or higher?

Ta.

Judging by the exam papers posted on PH the other day the GCSE paper would've said, "1+1=2, what does 1+1 equal"?

[pugwash4x4]

It was in an A-level module SWMBO took about 12 years ago- would be interested to know if it still was!

[MoleVision]

elster said:

Ah so the first one replace the top line with u, integrate in terms of u.

Yeh I think so, cant remember the procedure exactly... dont think expanding it really helps cos you still end up with having to integrate rootx/(x^2).

elster said:

As for the second one, how would I do that?

well you are integrating with respect to squiggle or "Zeta" as some call it..(Z when written below)... so treat the x^2 and the av as simple constants then its basic integration.

the x^2 then integrates to Z(x^2)
the 2/Z integrates to 2lnZ or something (thats a guess - you will need to check)
the avZ integrates to (av(Z^2))/2

I think.
Again, someone may want to tell me I'm wrong (or hopefully right!)

[CobolMan]

I hope this comes out OK:

[elster]

CobolMan said:

I hope this comes out OK:

Ah so it isn't done by substitution.

It looks so easy now you have written it down like that. Between stage 2 and 3 is the bit I was unsure of.

Thanks.

[elster]

MoleVision said:

well you are integrating with respect to squiggle or "Zeta" as some call it..(Z when written below)... so treat the x^2 and the av as simple constants then its basic integration.

the x^2 then integrates to Z(x^2)
the 2/Z integrates to 2lnZ or something (thats a guess - you will need to check)
the avZ integrates to (av(Z^2))/2

I think.
Again, someone may want to tell me I'm wrong (or hopefully right!)

That is all fine, I was just unsure what the alpha v meant. If I just class it as alpha-v times zeta.

So when you are integrating in terms of zeta, you treat and other letters as zeta^0.

[CobolMan]

HTH elster - you wouldn't believe the 'fun' I had getting the formatting correct though

[elster]

CobolMan said:

HTH elster - you wouldn't believe the 'fun' I had getting the formatting correct though

What do you use to write the formula?


Thanks all for the help as well guys.

[CobolMan]

elster said:

CobolMan said:

HTH elster - you wouldn't believe the 'fun' I had getting the formatting correct though

What do you use to write the formula?


Thanks all for the help as well guys.

I used the formula editor in a NeoOffice word processing document then took a screen grab of the file onto my desktop, saved it as a .png in Preview and then uploaded it. Good luck with your course.