Pulling A Pint - How Much Energy Required?
Discussion
Bit of an off the wall question here - but a Google search has not turned up much. How much energy is required to pull a pint from a traditional handpull pump?
I'd like to try and work out how much energy is going to be exerted by our barstaff this weekend, and from that how many calories have been burned through their efforts to pull circa 20,000 pints.
Our handpulls dispense a quarter of a pint from each pull - there's no gravity involved as the casks are at the same level (if not slightly below) the level of the pumps. The pull from cask to pump will be roughly five metres.
Is there a theoretical way to work this out? Or do I need to measure the force required to pull a pint somehow? (Rig up some Heath Robinson device that has weights and does a complete pull of the handle at the same speed as a normal member of the bar staff?)
I'd like to try and work out how much energy is going to be exerted by our barstaff this weekend, and from that how many calories have been burned through their efforts to pull circa 20,000 pints.
Our handpulls dispense a quarter of a pint from each pull - there's no gravity involved as the casks are at the same level (if not slightly below) the level of the pumps. The pull from cask to pump will be roughly five metres.
Is there a theoretical way to work this out? Or do I need to measure the force required to pull a pint somehow? (Rig up some Heath Robinson device that has weights and does a complete pull of the handle at the same speed as a normal member of the bar staff?)
work required = force x distance
assume horizontal motion, simply find the force required to move the pump at the desired rate. use a strain gauge or something and pull it yourself. use the horizontal travel of the pump as the distance.
it'll be ball park, as the pump obviously moved radially.
or stop being such a geek and pour my beer dammit!
assume horizontal motion, simply find the force required to move the pump at the desired rate. use a strain gauge or something and pull it yourself. use the horizontal travel of the pump as the distance.
it'll be ball park, as the pump obviously moved radially.
or stop being such a geek and pour my beer dammit!
Edited by shirt on Monday 21st June 21:10
condor said:
You've got to be having a laugh 
Best way is for you to try it for yourself
Far from a laugh! Best way is for you to try it for yourself
Leithen said:
condor said:
You've got to be having a laugh
Best way is for you to try it for yourself
Far from a laugh! Best way is for you to try it for yourself
I think it depends on where you have the sparkler as to what the likely resistance force might be.
Weather is looking good for this weekend, so hope you get plenty of sales
As above - try and get a scale to work out how much force is required to pull the handle. Work out the distance the handle must move.
You could use a weighing scale and convert your Kilogrammes into Newtons.
And then as above - work done = force X distance (all in metric, so use metres), and that will give you it in joules.
I presume you can then convert this to Calories or number of Mars bars or something.
You could use a weighing scale and convert your Kilogrammes into Newtons.
And then as above - work done = force X distance (all in metric, so use metres), and that will give you it in joules.
I presume you can then convert this to Calories or number of Mars bars or something.
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