Simple Maths Problem
Discussion
dr_gn said:
There are two identical cakes. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the cakes is left?
If that's the question verbatim, the answer is 7/48. Try this:
There are ten identical cakes. Person A takes 1/2 of one cake, Person B takes 1/2 of another cake. The other cakes are left untouched. What fraction of the cakes is left?
You started with ten cakes. With a bit of squashing together* you end up with 9. You have 9/10 of the cakes left.
Do the fractions thing:
You're left with 1/2 + 1/2 + 8, = 9. 9 isn't a fraction though, so you need a denominator, and that's the total number of cakes.
In the problem as presented, you're left with 1/6 of one and 1/8 of another = 7/24. You need then to divide that by the total number of cakes to get your answer, which gets you to 7/48.
Very badly worded question though, and if the set answer is 7/24 either the question setter or the marker has gone astray.
*you could say that you actually have 8 cakes left, and two bits of cake. So the answer is 8/10, and in the question as set you have no (zero) cakes left, only some bits - if you treat "cakes" and meaning "whole cakes".
Greg66 said:
dr_gn said:
There are two identical cakes. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the cakes is left?
If that's the question verbatim, the answer is 7/48. Try this:
There are ten identical cakes. Person A takes 1/2 of one cake, Person B takes 1/2 of another cake. The other cakes are left untouched. What fraction of the cakes is left?
You started with ten cakes. With a bit of squashing together* you end up with 9. You have 9/10 of the cakes left.
Do the fractions thing:
You're left with 1/2 + 1/2 + 8, = 9. 9 isn't a fraction though, so you need a denominator, and that's the total number of cakes.
In the problem as presented, you're left with 1/6 of one and 1/8 of another = 7/24. You need then to divide that by the total number of cakes to get your answer, which gets you to 7/48.
Very badly worded question though, and if the set answer is 7/24 either the question setter or the marker has gone astray.
*you could say that you actually have 8 cakes left, and two bits of cake. So the answer is 8/10, and in the question as set you have no (zero) cakes left, only some bits - if you treat "cakes" and meaning "whole cakes".
There are two identical cakes on a plate. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the plate of cakes is left?
Try this one-
A farmer raises ten turkeys. One customer eats half a turkey another customer eats a third of a turkey, what fraction of the turkeys is left?
a) 11/12
b) 9/10
c) 4/5
Toltec said:
Greg66 said:
dr_gn said:
There are two identical cakes. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the cakes is left?
If that's the question verbatim, the answer is 7/48. Try this:
There are ten identical cakes. Person A takes 1/2 of one cake, Person B takes 1/2 of another cake. The other cakes are left untouched. What fraction of the cakes is left?
You started with ten cakes. With a bit of squashing together* you end up with 9. You have 9/10 of the cakes left.
Do the fractions thing:
You're left with 1/2 + 1/2 + 8, = 9. 9 isn't a fraction though, so you need a denominator, and that's the total number of cakes.
In the problem as presented, you're left with 1/6 of one and 1/8 of another = 7/24. You need then to divide that by the total number of cakes to get your answer, which gets you to 7/48.
Very badly worded question though, and if the set answer is 7/24 either the question setter or the marker has gone astray.
*you could say that you actually have 8 cakes left, and two bits of cake. So the answer is 8/10, and in the question as set you have no (zero) cakes left, only some bits - if you treat "cakes" and meaning "whole cakes".
There are two identical cakes on a plate. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the plate of cakes is left?
Try this one-
A farmer raises ten turkeys. One customer eats half a turkey another customer eats a third of a turkey, what fraction of the turkeys is left?
a) 11/12
b) 9/10
c) 4/5
dr_gn said:
Greg66 said:
dr_gn said:
There are two identical cakes. Person A takes 5/6 of one cake, person B takes 7/8 of the other cake. What fraction of the cakes is left?
If that's the question verbatim, the answer is 7/48. 1/6 remains of one cake, 1/8 of the other.
We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
boyse7en said:
FredClogs said:
Jesus... 4/24 + 3/24 is 7/24 not 7/48...
Don't you start! I was just getting my head round this... I've gone with the answer being 7/24 of a cake, or 7/48 of the cakes
Alias218 said:
1/6 remains of one cake, 1/8 of the other.
We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
But you could say that you've got 8 slices left from one cake of 48 slices, and 6 slices left from the other cake of 48 slices.We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
So that is 14 slices left out of a total of 96 slices.
Cancel down and the answer is 7/48
The question is badly written, but taken literally it asks for a single answer to be provided as a fraction, and for the unit of that answer to be given in "the cakes". Not 1 cake, not 3 cakes, the (i.e. 2) cakes. Define the units of your answer to remove ambiguity.
7/48 of the two cakes remain.
7/48 of the two cakes remain.
boyse7en said:
Alias218 said:
1/6 remains of one cake, 1/8 of the other.
We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
But you could say that you've got 8 slices left from one cake of 48 slices, and 6 slices left from the other cake of 48 slices.We need to find a common denominator: 6*8=48.
Now the numerators need to be adjusted to match the new denominators: 6 goes into 48 eight times so the 1 becomes an 8 for 8/48 (the same as 1/6)
8 goes into 48 six times so the 1 becomes a 6 for 6/48 (the same as 1/8).
Add these together: 8/48 + 6/48= 14/48 (the denominator does not change).
Cancel down: 7/24.
And there is your answer.
So the answer, depending on how you view the question, is either 1/6 and 1/8 or 7/24.
So that is 14 slices left out of a total of 96 slices.
Cancel down and the answer is 7/48
However, it is also mathematically wrong.
Lets turn the fractions into decimals, for ease of visualisation. So:
3/24 = 0.125
4/24 = 0.167
0.125 + 0.167 = 0.291, we can all agree on that.
Incidentally, 7/24 = 0.291.
What you are doing is taking a whole (24) and turning it into two wholes (48). Makes sense, there are two 24 piece cakes therefore 48 pieces.
However, if we take 0.125 of 1 cake and 0.167 of 1 cake we see that when we add them using the two cake logic:
0.125/1 + 0.167/1 = 0.291/2 (as 3/24 + 4/24 = 7/48)
But then when we strip that right back: 0.125/1 = 0.125 and 0.167/1 = 0.167 and 0.291/2 = 0.145
The two cake logic states that 0.125 + 0.167 = 0.145, which it most certainly does not. It equals 0.291 or 7/24.
Incidentally, 0.145 = 7/48.
I had to scratch my head a little to get past the two cake image, which does lead you to conclude that 3/24 and 4/24 = 7/48. But mathematically, it doesn't. It can't. by adding the denominators, the amount of cake is being doubled, which then halves the amount of cake, as a fraction, that is left!
It's a very misleading question that can lead you down the garden path, but if you stick to mathematic principles you won't go wrong.
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