Geodesic dome triangles

Geodesic dome triangles

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205alive

Original Poster:

6,087 posts

177 months

Friday 8th February 2013
quotequote all
I'm constructing a geodesic dome from cardboard. The first of the two triangles I'm using is equilateral with a side length of 345mm and height of 300mm. The second should be isocelean (sic?), with one side being the same 345mm - but what should the remaining side lengths be?

Can anyone give me the easiest formula to determine the unknown side lengths, please?

205alive

Original Poster:

6,087 posts

177 months

Friday 8th February 2013
quotequote all
Perpendicular height.

205alive

Original Poster:

6,087 posts

177 months

Friday 8th February 2013
quotequote all
Devil2575 said:
Does the size of the second triangle not depend on how big you wish to make the dome?
Er...pass!

205alive

Original Poster:

6,087 posts

177 months

Friday 8th February 2013
quotequote all
Devil2575 said:
http://science.howstuffworks.com/engineering/struc...

According to this link you only need one one size of equilateral triangle.
So it does, paragraph six line two - thanks for that, been a bit confused - I found a good geodesic model for google sketchup, but the two triangles used in the model definitely have different areas, according to the face/component/etc info you can bring up.

Will find out tomorrow when I set about my cardboard triangles.

205alive

Original Poster:

6,087 posts

177 months

Saturday 9th February 2013
quotequote all
Just to update, it hasn't really worked out so far and, despite the ray of false hope offered yesterday, looks like common geodesic wisdom is suggesting it won't happen.

I did get an icosahedron out of it, as well as various more useless structures. Will have another crack tomorrow just in case there is the possibility of even knocking a third of a sphere up, as I would consider that a small but exciting success, given the current status of my life/empty void.

205alive

Original Poster:

6,087 posts

177 months

Monday 11th February 2013
quotequote all
In view of the results, steohedron is more appropriate (rhymes with 'light'). Never mind.